Question on: JSS3 Mathematics - Variations
If π§ varies jointly as π₯ and π¦, and π§=36 when π₯=3 and π¦=4, find π§ when π₯=6 and π¦=2.
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Given π§=ππ₯π¦, substituting the given values:
36=πβ 3β 4
Solving for π: π=36/12
=3
Now, find π§ when π₯=6 and π¦=2:
π§=3β 6β 2=36
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